$$(20-2x)\cdot(10-2x)x = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = 5 & x_3 = 10 \end{matrix} $$
Explanation
$$ \begin{aligned} (20-2x)\cdot(10-2x)x &= 0&& \text{simplify left side} \\[1 em](200-40x-20x+4x^2)x &= 0&& \\[1 em](4x^2-60x+200)x &= 0&& \\[1 em]4x^3-60x^2+200x &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ 4x^{3}-60x^{2}+200x = 0 } $, first we need to factor our $ x $.
$$ 4x^{3}-60x^{2}+200x = x \left( 4x^{2}-60x+200 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ 4x^{2}-60x+200 = 0$.
$ 4x^{2}-60x+200 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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