$$ \begin{aligned} \frac{2}{3}x+12 &= 0&& \text{multiply ALL terms by } \color{blue}{ 3 }. \\[1 em]3 \cdot \frac{2}{3}x+3\cdot12 &= 3\cdot0&& \text{cancel out the denominators} \\[1 em]2x+36 &= 0&& \text{ move the constants to the right } \\[1 em]2x &= -36&& \text{ divide both sides by $ 2 $ } \\[1 em]x &= -\frac{36}{2}&& \\[1 em]x &= -18&& \\[1 em] \end{aligned} $$
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