$$ \begin{aligned} \frac{19+5h}{3+h} &= 0&& \text{multiply ALL terms by } \color{blue}{ 3+h }. \\[1 em](3+h)\frac{19+5h}{3+h} &= (3+h)\cdot0&& \text{cancel out the denominators} \\[1 em]19+5h &= 0&& \text{ move the constants to the right } \\[1 em]5h &= -19&& \text{ divide both sides by $ 5 $ } \\[1 em]h &= -\frac{19}{5}&& \\[1 em] \end{aligned} $$
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