$$(15x-8)^2 = 4$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 2 }{ 3 } & x_2 = \dfrac{ 2 }{ 5 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (15x-8)^2 &= 4&& \text{simplify left side} \\[1 em]225x^2-240x+64 &= 4&& \text{move all terms to the left hand side } \\[1 em]225x^2-240x+64-4 &= 0&& \text{simplify left side} \\[1 em]225x^2-240x+60 &= 0&& \\[1 em] \end{aligned} $$
$ 225x^{2}-240x+60 = 0 $ is a quadratic equation.
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