$$\frac{1}{3}x+1-5 = 0$$

$$ \begin{aligned} \frac{1}{3}x+1-5 &= 0&& \text{multiply ALL terms by } \color{blue}{ 3 }. \\[1 em]3 \cdot \frac{1}{3}x+3\cdot1-3\cdot5 &= 3\cdot0&& \text{cancel out the denominators} \\[1 em]x+3-15 &= 0&& \text{simplify left side} \\[1 em]x-12 &= 0&& \text{ move the constants to the right } \\[1 em]x &= 12&& \\[1 em]x &= 12&& \\[1 em] \end{aligned} $$

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