$\frac{\frac{1}{x + 2}}{3 + x} = 0$

Answer

This equation has no solution.

Explanation

\frac{\frac{1}{x + 2}}{3 + x} (3 + x) (x + 2) \frac{\frac{1}{x + 2}}{3 + x} 1 = 0 = (3 + x) (x + 2) \cdot 0 = 0 multiply ALL terms by (3 + x) (x + 2) . cancel out the denominators

Since the statement $1 = 0$ is FALSE, we conclude that the equation has no solution.

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This equation has no solution.

$\frac{\frac{1}{x + 2}}{3 + x} = 0$