$$(-6x-3)\cdot(-5-4x) = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 1 }{ 2 } & x_2 = -\dfrac{ 5 }{ 4 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (-6x-3)\cdot(-5-4x) &= 0&& \text{simplify left side} \\[1 em]30x+24x^2+15+12x &= 0&& \\[1 em]24x^2+42x+15 &= 0&& \\[1 em] \end{aligned} $$
$ 24x^{2}+42x+15 = 0 $ is a quadratic equation.
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