$$(w+3)(4w+5) = 0$$
Answer
$$ \begin{matrix}w_1 = -3 & w_2 = -\dfrac{ 5 }{ 4 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (w+3)(4w+5) &= 0&& \text{simplify left side} \\[1 em]4w^2+5w+12w+15 &= 0&& \\[1 em]4w^2+17w+15 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}+17x+15 = 0 $ is a quadratic equation.
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