$$(2x^2-3)^2 = 0$$
Answer
$$ \begin{matrix}x_1 = 1.22474 & x_2 = -1.22474 & x_3 = -1.22475 \end{matrix} $$
Explanation
$$ \begin{aligned} (2x^2-3)^2 &= 0&& \text{simplify left side} \\[1 em]4x^4-12x^2+9 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using quartic formulas
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