$$\frac{(1-x)\cdot7}{x} = 0$$

$$ \begin{aligned} \frac{(1-x)\cdot7}{x} &= 0&& \text{multiply ALL terms by } \color{blue}{ x }. \\[1 em]x \cdot \frac{(1-x)\cdot7}{x} &= x\cdot0&& \text{cancel out the denominators} \\[1 em]-7x+7 &= 0&& \text{ move the constants to the right } \\[1 em]-7x &= -7&& \text{ divide both sides by $ -7 $ } \\[1 em]x &= \frac{-7}{-7}&& \\[1 em]x &= 1&& \\[1 em] \end{aligned} $$

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