To find angle $ \alpha $ use formula:
$$ \sin \left( \frac{ \alpha }{ 2 } \right) = \dfrac{ d_2 }{ d_1 } $$After substituting $ d_2 = \frac{ 1256 }{ 5 } $ and $ d_1 = \frac{ 2497 }{ 10 } $ we have:
$$ \sin \left( \frac{ \alpha }{ 2 } \right) = \dfrac{ \frac{ 1256 }{ 5 } }{ \frac{ 2497 }{ 10 } } $$ $$ \sin \left( \frac{ \alpha }{ 2 } \right) = \frac{ 2512 }{ 2497 } $$ $$ \frac{ \alpha }{ 2 } = \arcsin\left( \frac{ 2512 }{ 2497 } \right) $$$ \arcsin(1.006) $ is not defined $ \Longrightarrow $ The problem has no solution.