Find the height $ h $ of a rhombus if side $a = 5$ and angle $\alpha = 60^o$.
Answer
$h = \frac{ 5 \sqrt{ 3}}{ 2 }$
Explanation
To find height $ h $ use formula:
$$ \sin \left( \alpha \right) = \dfrac{ h }{ a } $$After substituting $ \alpha = 60^o $ and $ a = 5 $ we have:
$$ \sin( 60^o ) = \dfrac{ h }{ 5 } $$ $$ \frac{\sqrt{ 3 }}{ 2 } = \dfrac{ h }{ 5 } $$$$ h = \frac{\sqrt{ 3 }}{ 2 } \cdot 5 $$$$ h = \frac{ 5 \sqrt{ 3}}{ 2 } $$This page was created using
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