Find the diagonal $ d_2 $ of a rhombus if side $a = 8$ and diagonal $d_1 = 10$.
Answer
$d_2 = 2 \sqrt{ 39 }$
Explanation
To find diagonal $ d2 $ use formula:
$$ d_1^2 + d_2^2 = 4 \cdot a^2 $$After substituting $ d_1 = 10 $ and $ a = 8 $ we have:
$$ 10^2 + d_2^2 = 4 \cdot 8^2 $$ $$ 100 + d_2^2 = 256 $$ $$ d_2^2 = 256 - 100 $$ $$ d_2^2 = 156 $$ $$ d_2 = \sqrt{ 156 } $$$$ d_2 = 2 \sqrt{ 39 } $$This page was created using
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