Find the diagonal $ d_2 $ of a rhombus if side $a = 3$ and diagonal $d_1 = \sqrt{ 30 }$.
Answer
$d_2 = \sqrt{ 6 }$
Explanation
To find diagonal $ d2 $ use formula:
$$ d_1^2 + d_2^2 = 4 \cdot a^2 $$After substituting $ d_1 = \sqrt{ 30 } $ and $ a = 3 $ we have:
$$ \left( \sqrt{ 30 } \right)^{ 2 } + d_2^2 = 4 \cdot 3^2 $$ $$ 30 + d_2^2 = 36 $$ $$ d_2^2 = 36 - 30 $$ $$ d_2^2 = 6 $$ $$ d_2 = \sqrt{ 6 } $$This page was created using
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