Find the diagonal $ d_2 $ of a rhombus if side $a = 28$ and diagonal $d_1 = 32$.
Answer
$d_2 = 8 \sqrt{ 33 }$
Explanation
To find diagonal $ d2 $ use formula:
$$ d_1^2 + d_2^2 = 4 \cdot a^2 $$After substituting $ d_1 = 32 $ and $ a = 28 $ we have:
$$ 32^2 + d_2^2 = 4 \cdot 28^2 $$ $$ 1024 + d_2^2 = 3136 $$ $$ d_2^2 = 3136 - 1024 $$ $$ d_2^2 = 2112 $$ $$ d_2 = \sqrt{ 2112 } $$$$ d_2 = 8 \sqrt{ 33 } $$This page was created using
Rhombus Calculator