Find the diagonal $ d_1 $ of a rhombus if side $a = 36$ and diagonal $d_2 = 36$.
Answer
$d_1 = 36 \sqrt{ 3 }$
Explanation
To find diagonal $ d1 $ use formula:
$$ d_1^2 + d_2^2 = 4 \cdot a^2 $$After substituting $ d_2 = 36 $ and $ a = 36 $ we have:
$$ d_1 ^ {\,2} + 36^2 = 4 \cdot 36^2 $$ $$ d_1 ^ {\,2} + 1296 = 5184 $$ $$ d_1 ^ {\,2} = 5184 - 1296 $$ $$ d_1 ^ {\,2} = 3888 $$ $$ d_1 = \sqrt{ 3888 } $$$$ d_1 = 36 \sqrt{ 3 } $$This page was created using
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