Find the diagonal $ d_1 $ of a rhombus if side $a = 34$ and diagonal $d_2 = 16$.
Answer
$d_1 = 4 \sqrt{ 273 }$
Explanation
To find diagonal $ d1 $ use formula:
$$ d_1^2 + d_2^2 = 4 \cdot a^2 $$After substituting $ d_2 = 16 $ and $ a = 34 $ we have:
$$ d_1 ^ {\,2} + 16^2 = 4 \cdot 34^2 $$ $$ d_1 ^ {\,2} + 256 = 4624 $$ $$ d_1 ^ {\,2} = 4624 - 256 $$ $$ d_1 ^ {\,2} = 4368 $$ $$ d_1 = \sqrt{ 4368 } $$$$ d_1 = 4 \sqrt{ 273 } $$This page was created using
Rhombus Calculator