Find the diagonal $ d_1 $ of a rhombus if side $a = 13$ and diagonal $d_2 = 16$.
Answer
$d_1 = 2 \sqrt{ 105 }$
Explanation
To find diagonal $ d1 $ use formula:
$$ d_1^2 + d_2^2 = 4 \cdot a^2 $$After substituting $ d_2 = 16 $ and $ a = 13 $ we have:
$$ d_1 ^ {\,2} + 16^2 = 4 \cdot 13^2 $$ $$ d_1 ^ {\,2} + 256 = 676 $$ $$ d_1 ^ {\,2} = 676 - 256 $$ $$ d_1 ^ {\,2} = 420 $$ $$ d_1 = \sqrt{ 420 } $$$$ d_1 = 2 \sqrt{ 105 } $$This page was created using
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