Find the perimeter $ P $ of a rhombus if side $a = 7 \sqrt{ 2 }$ and angle $\beta = 45^o$.
Answer
$P = 28 \sqrt{ 2 }$
Explanation
To find perimeter $ P $ use formula:
$$ P = 4 \cdot a $$After substituting $ a = 7 \sqrt{ 2 } $ we have:
$$ P = 4 \cdot 7 \sqrt{ 2 } $$ $$ P = 28 \sqrt{ 2 } $$This page was created using
Rhombus Calculator