Find the area $ A $ of a rhombus if diagonal $d_1 = 4 \sqrt{ 3 }$ and diagonal $d_2 = 4 \sqrt{ 2 }$.
Answer
$A = 8 \sqrt{ 6 }$
Explanation
To find area $ A $ use formula:
$$ A = \dfrac{ d_1 \cdot d_2 }{ 2 } $$After substituting $ d_1 = 4 \sqrt{ 3 } $ and $ d_2 = 4 \sqrt{ 2 } $ we have:
$$ A = \dfrac{ 4 \sqrt{ 3 } \cdot 4 \sqrt{ 2 } }{ 2 }$$$$ A = \dfrac{ 16 \sqrt{ 6 } }{ 2 } $$$$ A = 8 \sqrt{ 6 } $$This page was created using
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