Find the area $ A $ of a rhombus if side $a = 12$ and angle $\alpha = 60^o$.
Answer
$A = 72 \sqrt{ 3 }$
Explanation
To find area $ A $ use formula:
$$ A = \dfrac{ a \cdot a \cdot \sin( \alpha ) }{ 1 } $$After substituting $ a = 12 $ , $ a = 12 $ and $ \alpha = 60^o $ we have:
$$ A = \dfrac{ 12 \cdot 12 \cdot \sin( 60^o ) }{ 1 } $$ $$ A = \dfrac{ 12 \cdot 12 \cdot \frac{\sqrt{ 3 }}{ 2 } }{ 1 } $$ $$ A = \dfrac{ 144 \cdot \frac{\sqrt{ 3 }}{ 2 } }{ 1 } $$ $$ A = \dfrac{ 72 \sqrt{ 3 } }{ 1 } $$ $$ A = 72 \sqrt{ 3 } $$This page was created using
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