Find the side $ a $ of a rhombus if height $h = 1$ and angle $\alpha = 60^o$.
Answer
$a = \frac{ 2 \sqrt{ 3}}{ 3 }$
Explanation
To find side $ a $ use formula:
$$ \sin \left( \alpha \right) = \dfrac{ h }{ a } $$After substituting $ \alpha = 60^o $ and $ h = 1 $ we have:
$$ \sin( 60^o ) = \dfrac{ 1 }{ a } $$ $$ \frac{\sqrt{ 3 }}{ 2 } = \dfrac{ 1 }{ a } $$ $$ a = \dfrac{ 1 }{ \frac{\sqrt{ 3 }}{ 2 } } $$ $$ a = \frac{ 2 \sqrt{ 3}}{ 3 } $$This page was created using
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