To find angle $ \alpha $ use formula:
$$ \alpha + \beta = 90^o $$After substituting $ \beta = \frac{ 26317 }{ 200 }^o $ we have:
$$ \alpha + \frac{ 26317 }{ 200 }^o = 90^o $$ $$ \alpha = 90^o - \frac{ 26317 }{ 200 }^o $$ $$ \alpha = -\frac{ 8317 }{ 200 }^o $$The result has to be greater than zero. $ \Longrightarrow $ The problem has no solution.