Find the side $ a $ of a rhombus if diagonal $d_1 = 72$ and diagonal $d_2 = 18$.
Answer
$a = 9 \sqrt{ 17 }$
Explanation
To find side $ a $ use formula:
$$ d_1^2 + d_2^2 = 4 \cdot a^2 $$After substituting $ d_1 = 72 $ and $ d_2 = 18 $ we have:
$$ 72^2 + 18^2 = 4 \cdot a^2 $$ $$ 5184 + 324 = 4 \cdot a^2 $$ $$ 4 \cdot a^2 = 5508 $$ $$ a^2 = \frac{ 5508 }{ 4 } $$ $$ a^2 = 1377 $$ $$ a = \sqrt{ 1377 } $$$$ a = 9 \sqrt{ 17 } $$This page was created using
Rhombus Calculator