Find the side $ a $ of a rhombus if diagonal $d_1 = 26$ and diagonal $d_2 = 16$.
Answer
$a = \sqrt{ 233 }$
Explanation
To find side $ a $ use formula:
$$ d_1^2 + d_2^2 = 4 \cdot a^2 $$After substituting $ d_1 = 26 $ and $ d_2 = 16 $ we have:
$$ 26^2 + 16^2 = 4 \cdot a^2 $$ $$ 676 + 256 = 4 \cdot a^2 $$ $$ 4 \cdot a^2 = 932 $$ $$ a^2 = \frac{ 932 }{ 4 } $$ $$ a^2 = 233 $$ $$ a = \sqrt{ 233 } $$This page was created using
Rhombus Calculator