Find the side $ a $ of a rhombus if diagonal $d_1 = 14$ and diagonal $d_2 = 7$.
Answer
$a = \frac{ 7 \sqrt{ 5}}{ 2 }$
Explanation
To find side $ a $ use formula:
$$ d_1^2 + d_2^2 = 4 \cdot a^2 $$After substituting $ d_1 = 14 $ and $ d_2 = 7 $ we have:
$$ 14^2 + 7^2 = 4 \cdot a^2 $$ $$ 196 + 49 = 4 \cdot a^2 $$ $$ 4 \cdot a^2 = 245 $$ $$ a^2 = \frac{ 245 }{ 4 } $$ $$ a^2 = \frac{ 245 }{ 4 } $$ $$ a = \sqrt{ \frac{ 245 }{ 4 } } $$$$ a = \frac{ 7 \sqrt{ 5}}{ 2 } $$This page was created using
Rhombus Calculator