Find the side $ a $ of a rhombus if area $A = \frac{ 57 }{ 10 }$ and angle $\beta = \frac{ 5493 }{ 50 }^o$.
Answer
Problem has no solutions.
Explanation
To find angle $ \alpha $ use formula:
$$ \alpha + \beta = 90^o $$After substituting $ \beta = \frac{ 5493 }{ 50 }^o $ we have:
$$ \alpha + \frac{ 5493 }{ 50 }^o = 90^o $$ $$ \alpha = 90^o - \frac{ 5493 }{ 50 }^o $$ $$ \alpha = -\frac{ 993 }{ 50 }^o $$The result has to be greater than zero. $ \Longrightarrow $ The problem has no solution.
This page was created using
Rhombus Calculator