Find the area $ A $ of a rectangle if side $a = 6$ and diagonal $d = 10$.
Answer
$A = 48$
Explanation
STEP 1: find side $ b $
To find side $ b $ use Pythagorean Theorem:
$$ a^2 + b^2 = d^2 $$After substituting $ a = 6 $ and $ d = 10 $ we have:
$$ 6^2 + b^2 = 10^2 $$ $$ b^2 = 10^2 - 6^2 $$ $$ b^2 = 100 - 36 $$ $$ b^2 = 64 $$ $$ b = \sqrt{ 64 } $$$$ b = 8 $$STEP 2: find area $ A $
To find area $ A $ use formula:
$$ A = a \cdot b $$After substituting $ a = 6 $ and $ b = 8 $ we have:
$$ A = 6 \cdot 8 $$$$ A = 6 \cdot 8 $$$$ A = 48 $$This page was created using
Rectangle Calculator