Find the side $ b $ of a rectangle if side $a = \frac{ 79 }{ 10 }$ and perimeter $P = \frac{ 136 }{ 5 }$.
Answer
$b = \frac{ 57 }{ 10 }$
Explanation
To find side $ b $ use formula:
$$ P = 2 a + 2 b $$After substituting $ P = \frac{ 136 }{ 5 } $ and $ a = \frac{ 79 }{ 10 } $ we have:
$$ \frac{ 136 }{ 5 } = 2 \cdot \frac{ 79 }{ 10 } + 2 b $$ $$ \frac{ 136 }{ 5 } = \frac{ 79 }{ 5 } + 2 b $$ $$ 2 b = \frac{ 136 }{ 5 } - \frac{ 79 }{ 5 } $$ $$ 2 b = \frac{ 57 }{ 5 } $$ $$ b = \dfrac{ \frac{ 57 }{ 5 } }{ 2 } $$ $$ b = \frac{ 57 }{ 10 } $$This page was created using
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