Find the side $ a $ of a rectangle if side $b = 10$ and diagonal $d = 16$.
Answer
$a = 2 \sqrt{ 39 }$
Explanation
To find side $ a $ use Pythagorean Theorem:
$$ a^2 + b^2 = d^2 $$After substituting $ b = 10 $ and $ d = 16 $ we have:
$$ a ^ {\,2} + 10^2 = 16^2 $$ $$ a ^ {\,2} = 16^2 - 10^2 $$ $$ a ^ {\,2} = 256 - 100 $$ $$ a ^ {\,2} = 156 $$ $$ a = \sqrt{ 156 } $$$$ a = 2 \sqrt{ 39 } $$This page was created using
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