Answer
$$\frac{\sqrt{60}}{\sqrt{33}}=\frac{2\sqrt{55}}{11}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{\sqrt{60}}{\sqrt{33}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{\sqrt{60}}{\sqrt{33}}\frac{\sqrt{33}}{\sqrt{33}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{6\sqrt{55}}{33} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{ 6 \sqrt{ 55 } : \color{blue}{ 3 } } { 33 : \color{blue}{ 3 }} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{2\sqrt{55}}{11}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ \sqrt{33}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ \sqrt{60} } \cdot \sqrt{33} = 6 \sqrt{55} $$ Simplify denominator. $$ \color{blue}{ \sqrt{33} } \cdot \sqrt{33} = 33 $$ |
| ③ | Divide numerator and denominator by $ \color{blue}{ 3 } $. |
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