Answer
$$\frac{9}{-8+\sqrt{3}}=\frac{-72-9\sqrt{3}}{61}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{9}{-8+\sqrt{3}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{9}{-8+\sqrt{3}}\frac{-8-\sqrt{3}}{-8-\sqrt{3}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{-72-9\sqrt{3}}{64+8\sqrt{3}-8\sqrt{3}-3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{-72-9\sqrt{3}}{61}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ -8- \sqrt{3}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ 9 } \cdot \left( -8- \sqrt{3}\right) = \color{blue}{9} \cdot-8+\color{blue}{9} \cdot- \sqrt{3} = \\ = -72- 9 \sqrt{3} $$ Simplify denominator. $$ \color{blue}{ \left( -8 + \sqrt{3}\right) } \cdot \left( -8- \sqrt{3}\right) = \color{blue}{-8} \cdot-8\color{blue}{-8} \cdot- \sqrt{3}+\color{blue}{ \sqrt{3}} \cdot-8+\color{blue}{ \sqrt{3}} \cdot- \sqrt{3} = \\ = 64 + 8 \sqrt{3}- 8 \sqrt{3}-3 $$ |
| ③ | Simplify numerator and denominator |
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