Answer
$$\frac{7\sqrt{2}}{\sqrt{8}-\sqrt{7}}=28+7\sqrt{14}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{7\sqrt{2}}{\sqrt{8}-\sqrt{7}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{7\sqrt{2}}{\sqrt{8}-\sqrt{7}}\frac{\sqrt{8}+\sqrt{7}}{\sqrt{8}+\sqrt{7}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{28+7\sqrt{14}}{8+2\sqrt{14}-2\sqrt{14}-7} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{28+7\sqrt{14}}{1} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}28+7\sqrt{14}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ \sqrt{8} + \sqrt{7}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ 7 \sqrt{2} } \cdot \left( \sqrt{8} + \sqrt{7}\right) = \color{blue}{ 7 \sqrt{2}} \cdot \sqrt{8}+\color{blue}{ 7 \sqrt{2}} \cdot \sqrt{7} = \\ = 28 + 7 \sqrt{14} $$ Simplify denominator. $$ \color{blue}{ \left( \sqrt{8}- \sqrt{7}\right) } \cdot \left( \sqrt{8} + \sqrt{7}\right) = \color{blue}{ \sqrt{8}} \cdot \sqrt{8}+\color{blue}{ \sqrt{8}} \cdot \sqrt{7}\color{blue}{- \sqrt{7}} \cdot \sqrt{8}\color{blue}{- \sqrt{7}} \cdot \sqrt{7} = \\ = 8 + 2 \sqrt{14}- 2 \sqrt{14}-7 $$ |
| ③ | Simplify numerator and denominator |
| ④ | Remove 1 from denominator. |
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