Tap the blue circles to see an explanation.
$$ \begin{aligned}\frac{6}{\sqrt{90}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}} \frac{ 6 }{\sqrt{ 90 }} \times \frac{ \color{orangered}{\sqrt{ 90 }} }{ \color{orangered}{\sqrt{ 90 }}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{6\sqrt{90}}{90} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}} \frac{ 6 \sqrt{ 9 \cdot 10 }}{ 90 } \xlongequal{ } \\[1 em] & \xlongequal{ } \frac{ 6 \cdot 3 \sqrt{ 10 } }{ 90 } \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{18\sqrt{10}}{90} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}} \frac{ 18 \sqrt{ 10 } : \color{blue}{ 18 } }{ 90 : \color{blue}{ 18 } } \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{\sqrt{10}}{5}\end{aligned} $$ | |
① | Multiply both top and bottom by $ \color{orangered}{ \sqrt{ 90 }}$. |
② | In denominator we have $ \sqrt{ 90 } \cdot \sqrt{ 90 } = 90 $. |
③ | Simplify $ \sqrt{ 90 } $. |
④ | Divide both the top and bottom numbers by $ \color{blue}{ 18 }$. |