Answer
$$\frac{3}{27+10\sqrt{2}}=\frac{81-30\sqrt{2}}{529}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{3}{27+10\sqrt{2}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3}{27+10\sqrt{2}}\frac{27-10\sqrt{2}}{27-10\sqrt{2}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{81-30\sqrt{2}}{729-270\sqrt{2}+270\sqrt{2}-200} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{81-30\sqrt{2}}{529}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ 27- 10 \sqrt{2}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ 3 } \cdot \left( 27- 10 \sqrt{2}\right) = \color{blue}{3} \cdot27+\color{blue}{3} \cdot- 10 \sqrt{2} = \\ = 81- 30 \sqrt{2} $$ Simplify denominator. $$ \color{blue}{ \left( 27 + 10 \sqrt{2}\right) } \cdot \left( 27- 10 \sqrt{2}\right) = \color{blue}{27} \cdot27+\color{blue}{27} \cdot- 10 \sqrt{2}+\color{blue}{ 10 \sqrt{2}} \cdot27+\color{blue}{ 10 \sqrt{2}} \cdot- 10 \sqrt{2} = \\ = 729- 270 \sqrt{2} + 270 \sqrt{2}-200 $$ |
| ③ | Simplify numerator and denominator |
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