Tap the blue circles to see an explanation.
$$ \begin{aligned}\frac{3}{(5+\sqrt{2})^2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3}{25+5\sqrt{2}+5\sqrt{2}+2} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{3}{27+10\sqrt{2}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{3}{27+10\sqrt{2}}\frac{27-10\sqrt{2}}{27-10\sqrt{2}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}\frac{81-30\sqrt{2}}{729-270\sqrt{2}+270\sqrt{2}-200} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle5}{\textcircled {5}} } }}}\frac{81-30\sqrt{2}}{529}\end{aligned} $$ | |
① | $$ (5+\sqrt{2})^2 = \left( 5 + \sqrt{2} \right) \cdot \left( 5 + \sqrt{2} \right) = 25 + 5 \sqrt{2} + 5 \sqrt{2} + 2 $$ |
② | Simplify numerator and denominator |
③ | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ 27- 10 \sqrt{2}} $$. |
④ | Multiply in a numerator. $$ \color{blue}{ 3 } \cdot \left( 27- 10 \sqrt{2}\right) = \color{blue}{3} \cdot27+\color{blue}{3} \cdot- 10 \sqrt{2} = \\ = 81- 30 \sqrt{2} $$ Simplify denominator. $$ \color{blue}{ \left( 27 + 10 \sqrt{2}\right) } \cdot \left( 27- 10 \sqrt{2}\right) = \color{blue}{27} \cdot27+\color{blue}{27} \cdot- 10 \sqrt{2}+\color{blue}{ 10 \sqrt{2}} \cdot27+\color{blue}{ 10 \sqrt{2}} \cdot- 10 \sqrt{2} = \\ = 729- 270 \sqrt{2} + 270 \sqrt{2}-200 $$ |
⑤ | Simplify numerator and denominator |