Answer
$$\frac{2\sqrt{2}+5\sqrt{7}}{11\sqrt{3}}=\frac{2\sqrt{6}+5\sqrt{21}}{33}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{2\sqrt{2}+5\sqrt{7}}{11\sqrt{3}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{2\sqrt{2}+5\sqrt{7}}{11\sqrt{3}}\frac{\sqrt{3}}{\sqrt{3}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{2\sqrt{6}+5\sqrt{21}}{33}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ \sqrt{3}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ \left( 2 \sqrt{2} + 5 \sqrt{7}\right) } \cdot \sqrt{3} = \color{blue}{ 2 \sqrt{2}} \cdot \sqrt{3}+\color{blue}{ 5 \sqrt{7}} \cdot \sqrt{3} = \\ = 2 \sqrt{6} + 5 \sqrt{21} $$ Simplify denominator. $$ \color{blue}{ 11 \sqrt{3} } \cdot \sqrt{3} = 33 $$ |
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