Answer
$$\frac{2+\sqrt{3}}{3\sqrt{5}}=\frac{2\sqrt{5}+\sqrt{15}}{15}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{2+\sqrt{3}}{3\sqrt{5}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{2+\sqrt{3}}{3\sqrt{5}}\frac{\sqrt{5}}{\sqrt{5}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{2\sqrt{5}+\sqrt{15}}{15}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ \sqrt{5}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ \left( 2 + \sqrt{3}\right) } \cdot \sqrt{5} = \color{blue}{2} \cdot \sqrt{5}+\color{blue}{ \sqrt{3}} \cdot \sqrt{5} = \\ = 2 \sqrt{5} + \sqrt{15} $$ Simplify denominator. $$ \color{blue}{ 3 \sqrt{5} } \cdot \sqrt{5} = 15 $$ |
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