Answer
$$\frac{1+\sqrt{2}}{11-6\sqrt{2}}=\frac{23+17\sqrt{2}}{49}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{1+\sqrt{2}}{11-6\sqrt{2}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{1+\sqrt{2}}{11-6\sqrt{2}}\frac{11+6\sqrt{2}}{11+6\sqrt{2}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{11+6\sqrt{2}+11\sqrt{2}+12}{121+66\sqrt{2}-66\sqrt{2}-72} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{23+17\sqrt{2}}{49}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ 11 + 6 \sqrt{2}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ \left( 1 + \sqrt{2}\right) } \cdot \left( 11 + 6 \sqrt{2}\right) = \color{blue}{1} \cdot11+\color{blue}{1} \cdot 6 \sqrt{2}+\color{blue}{ \sqrt{2}} \cdot11+\color{blue}{ \sqrt{2}} \cdot 6 \sqrt{2} = \\ = 11 + 6 \sqrt{2} + 11 \sqrt{2} + 12 $$ Simplify denominator. $$ \color{blue}{ \left( 11- 6 \sqrt{2}\right) } \cdot \left( 11 + 6 \sqrt{2}\right) = \color{blue}{11} \cdot11+\color{blue}{11} \cdot 6 \sqrt{2}\color{blue}{- 6 \sqrt{2}} \cdot11\color{blue}{- 6 \sqrt{2}} \cdot 6 \sqrt{2} = \\ = 121 + 66 \sqrt{2}- 66 \sqrt{2}-72 $$ |
| ③ | Simplify numerator and denominator |
This page was created using
Rationalize Denominator Calculator