Answer
$$\frac{12}{\sqrt{6}-2}=\frac{12\sqrt{6}+24}{2}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{12}{\sqrt{6}-2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{12}{\sqrt{6}-2}\frac{\sqrt{6}+2}{\sqrt{6}+2} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{12\sqrt{6}+24}{6+2\sqrt{6}-2\sqrt{6}-4} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{12\sqrt{6}+24}{2}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ \sqrt{6} + 2} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ 12 } \cdot \left( \sqrt{6} + 2\right) = \color{blue}{12} \cdot \sqrt{6}+\color{blue}{12} \cdot2 = \\ = 12 \sqrt{6} + 24 $$ Simplify denominator. $$ \color{blue}{ \left( \sqrt{6}-2\right) } \cdot \left( \sqrt{6} + 2\right) = \color{blue}{ \sqrt{6}} \cdot \sqrt{6}+\color{blue}{ \sqrt{6}} \cdot2\color{blue}{-2} \cdot \sqrt{6}\color{blue}{-2} \cdot2 = \\ = 6 + 2 \sqrt{6}- 2 \sqrt{6}-4 $$ |
| ③ | Simplify numerator and denominator |
This page was created using
Rationalize Denominator Calculator