Answer
$$\frac{10\sqrt{12}-6\sqrt{3}}{1}=14\sqrt{3}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{10\sqrt{12}-6\sqrt{3}}{1}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}10\sqrt{12}-6\sqrt{3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}20\sqrt{3}-6\sqrt{3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}14\sqrt{3}\end{aligned} $$ | |
| ① | Remove 1 from denominator. |
| ② | $$ 10 \sqrt{12} =
10 \sqrt{ 2 ^2 \cdot 3 } =
10 \sqrt{ 2 ^2 } \, \sqrt{ 3 } =
10 \cdot 2 \sqrt{ 3 } =
20 \sqrt{ 3 } $$ |
| ③ | Combine like terms |
This page was created using
Rationalize Denominator Calculator