Tap the blue circles to see an explanation.
$$ \begin{aligned}\frac{1}{\sqrt{8}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}} \frac{ 1 }{\sqrt{ 8 }} \times \frac{ \color{orangered}{\sqrt{ 8 }} }{ \color{orangered}{\sqrt{ 8 }}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{1\sqrt{8}}{8} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{\sqrt{8}}{8} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}} \frac{\sqrt{ 4 \cdot 2 }}{ 8 } \xlongequal{ } \\[1 em] & \xlongequal{ } \frac{\sqrt{ 4 } \cdot \sqrt{ 2 }}{ 8 } \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}\frac{2\sqrt{2}}{8} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle5}{\textcircled {5}} } }}} \frac{ 2 \sqrt{ 2 } : \color{blue}{ 2 } }{ 8 : \color{blue}{ 2 } } \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{\sqrt{2}}{4}\end{aligned} $$ | |
① | Multiply both top and bottom by $ \color{orangered}{ \sqrt{ 8 }}$. |
② | In denominator we have $ \sqrt{ 8 } \cdot \sqrt{ 8 } = 8 $. |
③ | Simplify $ \sqrt{ 8 } $. |
④ | The square root of $ 4 $ is $ 2 $. |
⑤ | Divide both the top and bottom numbers by $ \color{blue}{ 2 }$. |