Answer
$$\frac{1}{\sqrt{6}-\sqrt{3}+2+1}=\frac{1}{\sqrt{6}-\sqrt{3}+3}$$
Explanation
| $$ \begin{aligned}\frac{1}{\sqrt{6}-\sqrt{3}+2+1}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{1}{\sqrt{6}-\sqrt{3}+3}\end{aligned} $$ | |
| ① | Simplify numerator and denominator |
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