$\frac{1}{4 - 2 3} = \frac{2 + 3}{2}$

Explanation

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$\frac{1}{4 - 2 3} \overset{◯}{1} \frac{1}{4 - 2 3} \frac{4 + 2 3}{4 + 2 3} \overset{◯}{2} \frac{4 + 2 3}{16 + 8 3 - 8 3 - 12} \overset{◯}{3} \frac{4 + 2 3}{4} \overset{◯}{4} \frac{2 + 3}{2}$
①	Multiply the numerator and denominator by the conjugate of the denominator . $4 + 23$ .
②	Multiply in a numerator. $1 \cdot (4 + 23) = 1 \cdot 4 + 1 \cdot 23 = = 4 + 23$ Simplify denominator. $(4 - 23) \cdot (4 + 23) = 4 \cdot 4 + 4 \cdot 23 - 23 \cdot 4 - 23 \cdot 23 = = 16 + 83 - 83 - 12$
③	Simplify numerator and denominator
④	Divide both numerator and denominator by 2.

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4−23​1​=22+3​​

$\frac{1}{4 - 2 3} = \frac{2 + 3}{2}$