Answer
$$\frac{-6}{8+\sqrt{2}}=\frac{-48+6\sqrt{2}}{62}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{-6}{8+\sqrt{2}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{-6}{8+\sqrt{2}}\frac{8-\sqrt{2}}{8-\sqrt{2}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{-48+6\sqrt{2}}{64-8\sqrt{2}+8\sqrt{2}-2} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{-48+6\sqrt{2}}{62}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ 8- \sqrt{2}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ -6 } \cdot \left( 8- \sqrt{2}\right) = \color{blue}{-6} \cdot8\color{blue}{-6} \cdot- \sqrt{2} = \\ = -48 + 6 \sqrt{2} $$ Simplify denominator. $$ \color{blue}{ \left( 8 + \sqrt{2}\right) } \cdot \left( 8- \sqrt{2}\right) = \color{blue}{8} \cdot8+\color{blue}{8} \cdot- \sqrt{2}+\color{blue}{ \sqrt{2}} \cdot8+\color{blue}{ \sqrt{2}} \cdot- \sqrt{2} = \\ = 64- 8 \sqrt{2} + 8 \sqrt{2}-2 $$ |
| ③ | Simplify numerator and denominator |
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