Answer
$$\frac{-10}{7+\sqrt{2}}=\frac{-70+10\sqrt{2}}{47}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{-10}{7+\sqrt{2}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{-10}{7+\sqrt{2}}\frac{7-\sqrt{2}}{7-\sqrt{2}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{-70+10\sqrt{2}}{49-7\sqrt{2}+7\sqrt{2}-2} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{-70+10\sqrt{2}}{47}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ 7- \sqrt{2}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ -10 } \cdot \left( 7- \sqrt{2}\right) = \color{blue}{-10} \cdot7\color{blue}{-10} \cdot- \sqrt{2} = \\ = -70 + 10 \sqrt{2} $$ Simplify denominator. $$ \color{blue}{ \left( 7 + \sqrt{2}\right) } \cdot \left( 7- \sqrt{2}\right) = \color{blue}{7} \cdot7+\color{blue}{7} \cdot- \sqrt{2}+\color{blue}{ \sqrt{2}} \cdot7+\color{blue}{ \sqrt{2}} \cdot- \sqrt{2} = \\ = 49- 7 \sqrt{2} + 7 \sqrt{2}-2 $$ |
| ③ | Simplify numerator and denominator |
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