Tap the blue circles to see an explanation.
$$ \begin{aligned}\frac{(\sqrt{12}-\sqrt{3})^2}{1}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{12-6-6+3}{1} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}3\end{aligned} $$ | |
① | $$ (\sqrt{12}-\sqrt{3})^2 = \left( \sqrt{12}- \sqrt{3} \right) \cdot \left( \sqrt{12}- \sqrt{3} \right) = 12-6-6 + 3 $$ |
② | Remove 1 from denominator. |