Find the base area $B$ of a pyramid if height $h = 7.2 cm$ and slant height $s = 9.7 cm$ .

Answer

$169 cm^{2}$

Explanation

STEP 1: find side $a$

To find side $a$ use Pythagorean Theorem:

h^{2} + \frac{a ^{2}}{4} = s^{2}

After substituting $h = 7.2 cm$ and $s = 9.7 cm$ we have:

(7.2 cm)^{2} + \frac{a ^{2}}{4} = (9.7 cm)^{2}

\frac{a ^{2}}{4} = (9.7 cm)^{2} - (7.2 cm)^{2}

\frac{a ^{2}}{4} = 94.09 cm^{2} - 51.84 cm^{2}

a^{2} = 42.25 cm^{2} \cdot 4

a^{2} = 169 cm^{2}

a = 169 cm^{2}

a = 13 cm

STEP 2: find base area $B$

To find base area $B$ use formula:

B = a^{2}

After substituting $a = 13 cm$ we have:

B = (13 cm)^{2}

B = 169 cm^{2}

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Find the base area B of a pyramid if height h=7.2cm and slant height s=9.7cm.

169cm2

Find the base area $B$ of a pyramid if height $h = 7.2 cm$ and slant height $s = 9.7 cm$ .

$169 cm^{2}$