To find base diagonal $ d $ use Pythagorean Theorem:
$$ h^2 + \frac{ d^2 }{ 4 } = e^2 $$After substituting $ h = 6 $ and $ e = 6 $ we have:
$$ 6^2 + \frac{ d^2 }{ 4 } = 6^2 $$ $$ \frac{ d^2 }{ 4 } = 6^2 - 6^2 $$ $$ \frac{ d^2 }{ 4 } = 36 - 36 $$ $$ d^2 = 0 \cdot 4 $$ $$ d^2 = 0 $$This equation has no solution $ \Longrightarrow $ The problem has no solution.