Find the base area $ B $ of a pyramid if slant height $s = 3$ and lateral surface $L = 13$.
Answer
$B = \frac{ 169 }{ 36 }$
Explanation
STEP 1: find side $ a $
To find side $ a $ use formula:
$$ L = 2 \cdot a \cdot s $$After substituting $ L = 13 $ and $ s = 3 $ we have:
$$ 13 = 2 \cdot a \cdot 3 $$$$ 13 = 6 \cdot a $$$$ a = \dfrac{ 13}{ 6 } $$$$ a = \frac{ 13 }{ 6 } $$STEP 2: find base area $ B $
To find base area $ B $ use formula:
$$ B = a^2 $$After substituting $ a = \frac{ 13 }{ 6 } $ we have:
$$ B = \left(\frac{ 13 }{ 6 }\right)^2 $$ $$ B = \frac{ 169 }{ 36 } $$This page was created using
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